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-0.5x^2+5x+12=0
a = -0.5; b = 5; c = +12;
Δ = b2-4ac
Δ = 52-4·(-0.5)·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*-0.5}=\frac{-12}{-1} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*-0.5}=\frac{2}{-1} =-2 $
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